A cricket ball of mass $145\; gm$ is moving with a velocity of $14\;m/s$ and is being hit by a bat, so that the ball is turned back with a velocity of $22\;m/s$. The force of blow acts on the ball for $0.015\; sec$. Find the average force exerted by the bat on the ball.

Given,

Mass of cricket ball $(m) = 145 \; gm = 0.145 \; kg$

Initial Velocity of ball $(u) = 14 \; m/s$

Final velocity of ball $(v) = 22\;m/s$

Time of impact $(t) = 0.015 \; sec$

Average force exerted by the bat on the ball $(F) = ?$

We have, $F \; = \;$$\frac{m(v- u)}{t}$

$=$$\frac{0.145\;[22-(-14)]}{0.015}$           [∵ Being two velocities are opposite direction] 

$= 348\;N$

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