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Two charges 1106C and 4106C are separated by a distance of 2m. Determine the position of the null point.

Given, (need figure)
First charge (q1)=1106C
Second charge (q2)=4106C
Distance (r)=2m

Let C be the null point at a distance x from the charge.
At null point, Force due to charge (q1) = Force due to charge (q2)
or, 14πϵ0q1qx2=14πϵ0q2q(r+x)2
or, q1x2=q2(r+x)2
or, (r+x)2x2=41061106
or, (r+xx)2=4
or, (r+xx)=2
or, (2+xx)=2                             [∵ r = 2 m]
x=2m

∴ Position of the null point from the q1 charge is 2m


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