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A car travelling with a speed of 15m/s is braked and it slows down with uniform retardation. It covers a distance of 88m as its velocity reduces to 7m/s. If the car continues to slow down with the same rate, after what further distance will it be brought to rest?

Given;

Case I:
Initial Velocity (u)=15m/s
Distance Covered (s)=88m
Final Velocity v=7m/s
Retardation (a)=?
We have,
v2=u2+2as    ⇒   a=v2u22.s=72152288 =1m/s2

Case II:
Initial Velocity (u)=7m/s
Retardation (a)=1m/s2
Final Velocity (v)=0m/s
Distance Covered (s)=?

Again we have,
v2=u2+2as
s=v2u22(1)=24.5m
The car brought to be rest at a distance 24.5m.

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