What would be the acceleration of a block sliding down an inclined plane that makes an angle of 45° with the horizontal if the coefficient of sliding friction between two surfaces in 0.3?
Given,
Angle of inclination $(\theta)$ = 45°
Coefficient of Friction $(\mu)$ = 0.3
Downward Acceleration $(a)$ = ?
The downward force $= mg\;Sin\;\theta$
The frictional force = $\mu\;R = \mu\;mg\;Cos\theta$
No comments:
Post a Comment