Mass of copper ball (mb)=400gm=0.4kg
Mass of calorimeter (mc)=300gm=0.3kg
Mass of water (mw)=1kg
Initial temp of water and calorimeter (θ2)=20∘C
Final temp (θ)=50∘C
Specific heat capacity of copper ball (Sc)=400J/KgK
Specific heat capacity of water (Sw)=4200J/KgC
Temperature of ball (θ1)=?
From the principle of calorimetry,
Heat loss = Heat gain
mbSc(θ1−θ)=(mcSc+mwSw)(θ−θ2)
From the principle of calorimetry,
Heat loss = Heat gain
mbSc(θ1−θ)=(mcSc+mwSw)(θ−θ2)
or, 0.4∗400(θ1−50)=0.3∗400∗+1∗4200)(50−20)
or, 160(θ1−50)=129600
or, θ1=810+50=860∘C
∴ Temperature of ball is 860∘C
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