Processing math: 100%

A ball of copper of specific heat capacity 400J/KgK weighting 400gm is transferred from a furnace to a copper calorimeter of mass 300 gm and containing 1Kg of water at 20C. The temperature of water rises to 50C. What is the initial temperature of the ball?

Given,

Mass of copper ball (mb)=400gm=0.4kg


Mass of calorimeter (mc)=300gm=0.3kg

Mass of water (mw)=1kg

Initial temp of water and calorimeter (θ2)=20C

Final temp (θ)=50C

Specific heat capacity of copper ball (Sc)=400J/KgK

Specific heat capacity of water (Sw)=4200J/KgC

Temperature of ball (θ1)=?

From the principle of calorimetry,

Heat loss = Heat gain

mbSc(θ1θ)=(mcSc+mwSw)(θθ2)

or, 0.4400(θ150)=0.3400+14200)(5020)

or, 160(θ150)=129600

or, θ1=810+50=860C

Temperature of ball is 860C

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