(i) Using Kirchhoff's current law at point ′D′,
Current through R=6−4=2A
(ii) Applying Kirchhoff's voltage law in close loop ABCDA,
E=3∗6+4∗6=18+24=42V
(iii) Again, Applying Kirchhoff's voltage law in close loop AFEDA,
E−28=6∗4−R∗2
42−28=24−2R
2R=24−14=10
R=5Ω
(iv) If the circuit is broken from point ′P′ then,
Current(I)=VR+3=285+3 =3.5A
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