A glider with mass m=2kg sits on a frictionless horizontal air track, connected to a spring with force constant k=5N/m. You pull the glider, stretching the spring 0.1m and then release it with no initial velocity. The glider begins to move back towards ie equilibrium position (x=0). What is its velocity when x=0.08m?

Given,

Mass (m)=2kg
Force Constant (k)=5N/m
Amplitude (r)=0.1m
Position (x)=0.08m
Velocity at x=0.08m = ?

We have,
12mv2+12kx2=12kr2

By solving,
v=km(r2x2)
or, v=52((0.1)2(0.08)2)
or v=0.09m/s

∴ Velocity at x=0.08m is 0.09m/s.

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