Processing math: 100%

Three equal charges of 4.0107C are located at the corners of a right triangle whose sides are 6cm, 8cm and 10cm respectively. Find the force exerted on the charge located at 90 angle.

Given, (need figure)

Three equal charge (q1=q2=q3=4107C)
Distance (AB)=8cm=0.08m
Distance (BC)=6cm=0.06m
Distance (AC)=10cm=0.1m
Angle ABC=90
Force (F)=?

FAB=14πϵ0q1q2R2=9109(0.4106)2(0.08)2=0.225N
FBC=14πϵ0q1q2R2=9109(0.4106)2(0.06)2=0.40N
Force exerted on the charge located at 90 is,

F=(FAB)2+(FBC)2+2FABFBCCosθ
F=(0.225)2+(0.4)2+20.2250.4Cos90
F=0.46N

Return to Main menu

No comments:

Post a Comment