A car travelling with a speed of $15\;m/s$ is braked and it slows down with uniform retardation. It covers a distance of $88 \; m$ as its velocity reduces to $7 \;m/s$. If the car continues to slow down with same rate, after what further distance will it be brought to rest?

Given,

$u = 15\;m/s$

$v = 7\;m/s$

$S = 88\;m$

$a = \;?$

$v^2 = u^2 + 2\;a\;s$

$7^2 = 15^2 + 2 * a * 88$

⇒ $a = -1 \;m/s^2$

∴ Retardation = $1\;m/s^2$

As car is going to stop;

$u = 7\;m/s$

$v = 0$

$a = -1\;m/s$

$s = \;?$

$v^2 = u^2 + 2\;a\;s$

$0 = 7^2 + 2 * (-1) * s$

$2s = 49$

⇒ $s = 24.5\;m$

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