Calculate the acceleration of a block sliding down a slope of $30^0$. Given: coefficient of friction is 0.25 and $g = 9.8 m/s^2$

Given,

Angle of inclination $(\theta)$ = 30°

Coefficient of Friction $(\mu)$ = 0.25

Downward Acceleration $(a)$ = ?

The downward force $= mg\;Sin\;\theta$

The frictional force = $\mu\;R = \mu\;mg\;Cos\theta$

Net downward force along the plane is,

$F = mg\;Sin\theta - \mu\;mg\;Cos\theta = mg\;(Sin\;30 - 0.25 \; *\;Cos\;30) = mg\;*\; 0.283$

Then acceleration $a$ is given by,

$F = ma$     ⇒     $a =$$\frac{F}{m}$ = $\frac{mg\;*\;0.283}{m}$ = $10 * 0.283 = 2.83 \; m/s^2$

Return to Main Menu