Given, Capacitance (C)=33pF=33∗10−12F
Let, L be the self-inductance connected with the capacitance, so that the natural frequency of this LC circuit is 810KHz,
i.ef=810∗103Hz
Now, we have
f=12π√LC
L= 14π2(810∗103)2∗33∗10−12 =1.17∗10−3H
Thus, Inductance connected (L)=1.17∗10−3H
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