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The e.m.f of a battery A is balanced by a length 75 cm on a potentiometer wire. The emf of a standard cell 1.02 V is balanced by a length of 50 cm. What is the emf of A?

Given,
Let E1 be the emf of a cell A
Balancing length for A(l1)=75cm
Emf of standard cell (E2)=1.02V
Balancing length for E2(l2)=50cm
We know,
E1E2=l1l2
E1=75501.53V
Hence, emf of the cell A is 11.53V
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