Loading [MathJax]/jax/output/HTML-CSS/jax.js

A mass of 1kg is attached to the lower end of a string 1m long whose upper end is fixed. The mass is made to rotate in a horizontal circle of radius 60m. If the circular speed of the mass is constant. Find the tension in the string and the period of motion.

Given, (need figure)
Mass of the object (m)=1kg
Length of string (l)=1m
Radius of circle (r)=60cm=0.6m
Tension on the string (T)=?
Period of motion (t)=?

From Figure,
TCosθ=mg .......... (i)
TSinθ=mv2r .......... (ii)
We have,

tanθ=v2rg and            Sinθ= rl=0.61 =0.6
θ=Sin1(0.6)=36.87
Now, From the relation,
T= mgCosθ=110Cos(36.87) =12.5N

⇒ Tension on the string (T)=12.5N
Again from relation,
t=2πlCosθg
t= 2π1Cos(36.87)10 = 1.78Sec
⇒ Period of motion (t)=1.78Sec
Return to Main Menu

No comments:

Post a Comment