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A bob of mass 200gm is whirled in a horizontal circle of radius 50cm by a string inclined at 30 to the vertical. Calculate the tension in the string and the speed of the bob in the horizontal circle.

Given, (need figure)
Mass of the bob (m)=200gm=0.2kg
Radius of horizontal circle (r)=50cm=0.5m
Angle of inclination with vertical (θ)=30
Tension in the string (T)=?
Speed of the mass (v)=?

In case of the horizontal circle, we have
(i) To balance the weight of the body,           TCosθ=mg
T= mgCosθ=0.210Cos30 =2.3N
Tension in the string T=2.3N

(ii) To provide the necessary centripetal force,        TSinθ= Mv2r
v2= TSinθrm

v= 2.3Sin300.50.2 =1.69m/s

Speed of mass (v)=1.69m/s

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