An electron of mass $9.1 * 10^{-31}\;kg$ and charge $1.6 * 10^{-19}\;C$ is situated in a uniform electric field of intensity $1.2 * 10^{4}\;Vm^{-1}$. Find the time it takes to travel $1\; cm$ from rest.

Given,

Mass of electron $(m_e) = 9.1 \;* \;10^{-31}\;kg$

Charge of electron $(e) = 1.6 * 10^{-19}$

Electric field intensity $(E) = 1.2 * 10^4\;V/m$

Distance covered $(s) = 1\;cm = 100^{-2}\;m$

Time taken (t) = ?

We have,

$F = eE$

or, ma = eE

or, $a =$$\frac{eE}{m} = \frac{1.6 * 10^{-19} \;*\; 1.2 \;*\; 10^4}{9.1 \;*\; 10^{-31}}$$= 2.1 * 10^{15}\;m/s^2$

Now we have to calculate,

$S = ut \;+\;$$\frac{1}{2}$$at^2$

$S = 0 \;+\;$$\frac{1}{2}$$at^2$                                              [∵ $u = 0 \; m/s$]

$0.01 =$$\frac{1}{2}$$\;*\; 2.1 \;*\; 10^{15} \;*\; t^2$

⇒ $t = 3.1 \;*\; 10^{-9}\;Sec$

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