A ball of mass 4kg moving with a velocity 10m/s collides with another body of mass 16kg moving with 4m/s from the opposite direction and then coalesces into a single body. Compute the loss of energy on impact.
Given,
Mass of first ball (m1)=4kg
Initial velocity of first ball (u1)=10m/s
Mass of second ball (m2)=16kg
Initial velocity of second ball (u2)=4m/s
Loss of energy on impact (∇E)=?
Since ball are moving in opposite direction.
Then, from the principle of conservation of linear momentum,
m1.u1+m2.(−u2)=(m1+m2)v [v is the common velocity]
⇒ v=m1u1−m2u2m1+m2=4∗10−16∗44+16=−1.2m/s
[i.e. is in the direction of m2]
Kinetic Energy before collision E1=12m1u21+12m2u22
=12∗4∗102+12∗16∗42=328J
Kinetic Energy after collision Ef=12(m1+m2)v2
=12(4+16)∗(1.2)2=14.4J
Loss of energy on impact (∇E) = Kinetic Energy before collision - Kinetic Energy after collision.
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