A ball of mass $0.05\;kg$ strikes a smooth wall normally four times in $2$ seconds with a velocity of $10\;m/s$. Each time the ball rebounds with the same speed of $10\;m/s$. Calculate the average force on the wall.

Given,

Mass of ball $0.05\;kg$

Initial Velocity $(u) = 10\;m/s$

Final Velocity $(v) = (-10\;m/s)$  [Opposite in direction]

No. of striking $(n) = 4$ times

Time taken $(t) = 2\;sec$

Average force on wall $(F) = \;?$

We have,

$F = $$\frac{n(mv-mu)}{t}$    =    $\frac{4(10\;*\;0.05 - (-10 \;*\;0.05))}{2}$    =    $2\;N$

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