A ball of mass 0.05kg strikes a smooth wall normally four times in 2 seconds with a velocity of 10m/s. Each time the ball rebounds with the same speed of 10m/s. Calculate the average force on the wall.


Given,
Mass of ball 0.05kg
Initial Velocity (u)=10m/s
Final Velocity (v)=(10m/s)  [Opposite in direction]
No. of striking (n)=4 times
Time taken (t)=2sec
Average force on wall (F)=?
We have,

F=n(mvmu)t    =    4(100.05(100.05))2    =    2N

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